Перевод геометрических свойств в координаты

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2022-05-12 19:08:48 +03:00
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commit df8f21a07b
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#lang racket/base
(define (coordinations x1 y1 x2 y2 x3 y3 x4 y4 x5 y5)
(define (square x) (* x x))
(if (equal? (* (- x1 x2) (- y2 y3)) (* (- y1 y2) (- x2 x3)))
(displayln "Points 1, 2 and 3 lie on a common line.")
(displayln "Points 1, 2 and 3 do not lie on a common line."))
(if (equal? (* (- x1 x2) (- y3 y4)) (* (- y1 y2) (- x3 x4)))
(displayln "Lines (1,2) and (3,4) are parallel.")
(displayln "Lines (1,2) and (3,4) are not parallel."))
(if (equal? (+ (* (- x1 x2) (- x3 x4)) (* (- y1 y2) (- y3 y4))) 0 )
(displayln "Lines (1,2) and (3,4) are perpendicular.")
(displayln "Lines (1,2) and (3,4) are not perpendicular."))
(if (equal? (+ (square(- x1 x2)) (square(- y1 y2))) (+ (square(- x3 x4)) (square(- y3 y4))))
(displayln "Lines (1,2) and (3,4) have the same length.")
(displayln "Lines (1,2) and (3,4) do not have the same length.."))
(if (and (equal? (* 2 x1) (+ x2 x3)) (equal? (* 2 y1) (+ y2 y3)))
(displayln "Point 1 is the midpoint of line (2,3).")
(displayln "Point 1 is not the midpoint of line (2,3)."))
(if (and (equal? (* (- x1 x2) (- y2 y3)) (* (- y1 y2) (- x2 x3)) )
(equal? (* (- x1 x4) (- y4 y5)) (* (- y1 y4) (- x4 x5)) ) )
(displayln "Lines (2,3) and (4,5) meet at point 1.")
(displayln "Lines (2,3) and (4,5) do not intersect at point 1."))
(if (and (equal? x1 x2) (equal? y1 y2))
(displayln "Points 1 and 2 are the same.")
(displayln "Points 1 and 2 are not the same."))
)
(coordinations 0 1 0 0 0 1 1 1 2 2)

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# Перевод геометрических свойств в координаты
## Ссылка на видеоразбор
https://youtu.be/Nu43zpDrWuM
## Код из книги
let coordinations =
["collinear", (** Points 1, 2 and 3 lie on a common line **)
<<(1_x - 2_x) * (2_y - 3_y) = (1_y - 2_y) * (2_x - 3_x)>>;
"parallel", (** Lines (1,2) and (3,4) are parallel **)
<<(1_x - 2_x) * (3_y - 4_y) = (1_y - 2_y) * (3_x - 4_x)>>;
"perpendicular", (** Lines (1,2) and (3,4) are perpendicular **)
<<(1_x - 2_x) * (3_x - 4_x) + (1_y - 2_y) * (3_y - 4_y) = 0>>;
"lengths_eq", (** Lines (1,2) and (3,4) have the same length **)
<<(1_x - 2_x)^2 + (1_y - 2_y)^2 = (3_x - 4_x)^2 + (3_y - 4_y)^2>>;
"is_midpoint", (** Point 1 is the midpoint of line (2,3) **)
<<2 * 1_x = 2_x + 3_x /\ 2 * 1_y = 2_y + 3_y>>;
"is_intersection", (** Lines (2,3) and (4,5) meet at point 1 **)
<<(1_x - 2_x) * (2_y - 3_y) = (1_y - 2_y) * (2_x - 3_x) /\
(1_x - 4_x) * (4_y - 5_y) = (1_y - 4_y) * (4_x - 5_x)>>;
"=", (** Points 1 and 2 are the same **)
<<(1_x = 2_x) /\ (1_y = 2_y)>>];;
let coordinate = onatoms
(fun (R(a,args)) ->
let xtms,ytms = unzip
(map (fun (Var v) -> Var(v^"_x"),Var(v^"_y")) args) in
let xs = map (fun n -> string_of_int n^"_x") (1--length args)
and ys = map (fun n -> string_of_int n^"_y") (1--length args) in
subst (fpf (xs @ ys) (xtms @ ytms)) (assoc a coordinations));;
START_INTERACTIVE;;
coordinate <<collinear(a,b,c) ==> collinear(b,a,c)>>;;
END_INTERACTIVE;;